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0.2x^2-x+3=-1.2x^2+5.5x-2
We move all terms to the left:
0.2x^2-x+3-(-1.2x^2+5.5x-2)=0
We add all the numbers together, and all the variables
0.2x^2-(-1.2x^2+5.5x-2)-1x+3=0
We get rid of parentheses
0.2x^2+1.2x^2-5.5x-1x+2+3=0
We add all the numbers together, and all the variables
1.4x^2-6.5x+5=0
a = 1.4; b = -6.5; c = +5;
Δ = b2-4ac
Δ = -6.52-4·1.4·5
Δ = 14.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.5)-\sqrt{14.25}}{2*1.4}=\frac{6.5-\sqrt{14.25}}{2.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.5)+\sqrt{14.25}}{2*1.4}=\frac{6.5+\sqrt{14.25}}{2.8} $
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